By Seun Sambath
Seun Sambath, PhD
Phnom Penh 2010
Address: #M41, St.308, Sangkat Tonle Basac, Khan Chamkarmon,
Phnom Penh, Cambodia.
Tel: 012 659 848.
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Extra info for ACI 318-05 Mathcad in Concrete Structures
85 β1 fy ε u ε t ϕ = ϕ εt 2 bd = Mn R Mn Option 1: R b= d 2 Mn Option 2: R d= b 3 Option 3: k= b d= d Step 2. 85 f'c R As = max ρ ρmin b d Step 3. 976 mm 25mm 2 11. Design of Doubly Reinforced Beams ρ ρmax : the beam is singly reinforced (with tensile reinforcements only) ρ ρmax : the beam is doubly reinforced (with tensile and compression reinforcements) A. 2) c ε's = ε u c = d' c d' c εu ε u ε's B. 85 β1 ρ' fy ε u ε y d ρ ρcy : compression steel will yield f's = fy ρ ρcy : compression steel will not yield f's fy C.
85 f'c R ρ ρmax : the beam is doubly reinforced (concrete is not enough) ρ ρmax : the beam is singly reinforced As = max ρ ρmin b d (this is a required steel area) Step 3. 98 "is safe" if FS 1 The_beam "is safe" "is not safe" otherwise F. Determination of Concrete Dimension and Steel Area Given: M u f'c fy Find: b d As Step 1. 85 β1 fy ε u ε t ϕ = ϕ εt 2 bd = Mn R Mn Option 1: R b= d 2 Mn Option 2: R d= b 3 Option 3: k= b d= d Step 2. 85 f'c R As = max ρ ρmin b d Step 3.
9 M u ϕMn : the beam is rectangular M u ϕMn : the beam is tee Step 2. 255 cm 2 13.
ACI 318-05 Mathcad in Concrete Structures by Seun Sambath