Read e-book online ACI 318-05 Mathcad in Concrete Structures PDF

By Seun Sambath

Development MANAGEMENT
Concept-Develop-Execute-Finish
__________________________________________________________________________________
Seun Sambath, PhD
Concrete Structures
(ACI 318-05)
in Mathcad
Sixth Edition
Phnom Penh 2010
___________________________________________________________________________________
Address: #M41, St.308, Sangkat Tonle Basac, Khan Chamkarmon,
Phnom Penh, Cambodia.
Tel: 012 659 848.

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Extra info for ACI 318-05 Mathcad in Concrete Structures

Example text

85 β1   fy ε u  ε t   ϕ = ϕ εt 2 bd = Mn R Mn Option 1: R b= d 2 Mn Option 2: R d= b 3 Option 3: k= b d= d Step 2. 85 f'c  R  As = max ρ ρmin  b  d Step 3. 976  mm 25mm  2   11. Design of Doubly Reinforced Beams ρ  ρmax : the beam is singly reinforced (with tensile reinforcements only) ρ  ρmax : the beam is doubly reinforced (with tensile and compression reinforcements) A. 2) c ε's = ε u  c = d' c  d' c εu ε u  ε's B. 85 β1     ρ' fy ε u  ε y d ρ  ρcy : compression steel will yield f's = fy ρ  ρcy : compression steel will not yield f's  fy C.

85 f'c  R ρ  ρmax : the beam is doubly reinforced (concrete is not enough) ρ  ρmax : the beam is singly reinforced   As = max ρ ρmin  b  d (this is a required steel area) Step 3. 98 "is safe" if FS  1 The_beam  "is safe" "is not safe" otherwise F. Determination of Concrete Dimension and Steel Area Given: M u f'c fy Find: b  d As Step 1. 85 β1   fy ε u  ε t   ϕ = ϕ εt 2 bd = Mn R Mn Option 1: R b= d 2 Mn Option 2: R d= b 3 Option 3: k= b d= d Step 2. 85 f'c  R  As = max ρ ρmin  b  d Step 3.

9 M u  ϕMn : the beam is rectangular M u  ϕMn : the beam is tee Step 2. 255 cm 2 13.

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ACI 318-05 Mathcad in Concrete Structures by Seun Sambath


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